A boy hits a stationary billiard ball of mass 30 grams head on with a cue. The cue is in
contact with the ball for a time of 0.001 s and exerts a force of 50 N on it. Calculate:
a. The impulse on the ball on the direction of the force
b. Calculate the velocity of the ball just after it is struck
c. Calculate the acceleration of the ball during the time it is in contact with the cue.
d. Find the distance the ball reach in 9 s!![]()
contact with the ball for a time of 0.001 s and exerts a force of 50 N on it. Calculate:
a. The impulse on the ball on the direction of the force
b. Calculate the velocity of the ball just after it is struck
c. Calculate the acceleration of the ball during the time it is in contact with the cue.
d. Find the distance the ball reach in 9 s!
Diketahui:
m = 30 g = 0,03 kg
Δt = 0,001 s
F = 50 N
v1 = 0 m/s (mula2 bola diam)
Ditanyakan:
a) I?
b) v2?
c) a?
d) s?
Jawab:
a) Impuls
I = F x Δt
I = 50 x 0,001
I = 0,05 Ns
b) Kecepatan bola setelah tumbukan
I = ΔP
I = m x (v2 - v1)
0,05 = 0,03 x (v2 - 0)
0,05 = 0,03 x v2
0,05 / 0,03 = v2
5/3 = v2
v2 = 5/3 m/s
v2 = 1,67 m/s
c) Percepatan
a = (v2 - v1) / (t)
a = (1,67 - 0) / (0,001)
a = 1,67 / 0,001
a = 1670 m/s^2
d) Jarak tempuh
s = (v1 x t) + (1/2 x a x t^2)
s = (0 x 9) + (1/2 x 1670 x 9^2)
s = 0 + (835 x 81)
s = 67635 m
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